I am sooooo stuck on an apparently simple physics question Say an object starts at rest and travels 400m in 20s what is the acceleration. I tried google, half an hour and no answer or formula, little help?
Acceleration is uniform, Initial velocity is 0 Average speed is 20m/s Thats ALL the info I got Kedit:: Trial and error proved Final speed to be 40m/s and acceleration to be 2m/s/s... Now can anyone provide a simple formula so I can show working out?
But I need the acceleration, not speed ah, dont worry, I'll just "forget" the working out for this one, thanks anyway guys
yeah...i took physics class for 2 years...and HATED every single minute of it. I guess i don't have enough processing power to answer your question...you better ask someone else
Sorry I'm a bit late, had some other stuff to do, also needed to look up the formulas again since it's been ages since I've done this. legend: Δ = delta = the difference (final - initial) Since you know the distance and not the acceleration we should use the distance formula first to find the final velocity. d = 1/2 * Δv * Δt Fill in what we know 400 = 1/2 * v - 0* 20 - 0 400 = (1/2) * v - 0 * 20 Rearrange it to have velocity by itself. v = 400 / ((1/2) * 20) // and finally solve it. (400 divided by half of 20) v = 40 Thus the final velocity is 40 metres per second. You then need to find the acceleration, for this you need the following formula a = Δv/Δt Fill in what we know a = 40 - 0 / 20 - 0 a = 40 / 20 a = 2 Thus the acceleration rate is 2 metres per second increase per second.
if you suppose acceleration to be linear there is a simple formula s=(1/2)at^2+vt Where s: the distance covered a: acceleration t: time v: initial velocity(which here is 0) that makes 400=1/2*a*20*20 then a=2
