1. This forum is in read-only mode.

math problem i need help

Discussion in 'General Discussion' started by zzzzzzzzzz, Sep 13, 2009.

  1. zzzzzzzzzz

    zzzzzzzzzz Member

    how would one solve
    root(x-27) + root(x) = 9

    so solve for x
    and show steps
     
  2. CloudBoii12

    CloudBoii12 Well-Known Member

    It would help if you were telling us what kind of math problem it is :/
    Are you trying to expand, is it Linear equations, what?
     
  3. zzzzzzzzzz

    zzzzzzzzzz Member

    just solve for x
    what number does x have to be to make the equation equal to zero
    Post Merge: [time]1252814348[/time]
    i mean 9 not zero
     
  4. CloudBoii12

    CloudBoii12 Well-Known Member

    So you're square rooting them?
    As in like v/---- when it's written?

    If so, x = 36 :D
     
  5. Suiseiseki

    Suiseiseki Well-Known Member

    What is this, I don't even.
     
  6. Blade5406

    Blade5406 Well-Known Member

    Sorry, I lost x at the fair yesterday. He ran away. :(
     
  7. Hypr

    Hypr Well-Known Member

    Cloudboii, your posts are not helping him at all...

    zzzzzzzzzzz, here's the worked-out solution. Hopefully this helps you learn more about algebraic manipulation tricks.

    Solution

    EDIT (Sept. 21, 2009): Fixed link so that everyone can see it.
     
  8. CloudBoii12

    CloudBoii12 Well-Known Member

    Why not, my posts gave the answer :/

    You just showed an extended way of doing it, I gave him the straight out answer.
     
  9. Hypr

    Hypr Well-Known Member

    He was asking for steps to solve the problem. Giving just the answer only doesn't do much help to anyone.

     
  10. ricky_

    ricky_ Well-Known Member

    Fwiw, √ is useful in this.
     
  11. CloudBoii12

    CloudBoii12 Well-Known Member

    Oh, sorry >.<
    Jumped into the question xD
     
  12. NekoHennuli

    NekoHennuli Well-Known Member

    root(x-27) + root(x) = 9
    root(x-27) + root(x) = 9 // ^2
    (x-27)^2 + x^2 = 81
    x^2-729 + x^2 = 81
    x^2 + X^2 = 81 + 729
    2x^2 = 810
    2x^2 = 810 // /2
    x^2 = 405
    x^2 = 405 // root
    x = 20.124...
    x ~ 20

    I'm not sure if it's right. =P I need to check it with paper.
     
  13. tehuber1337

    tehuber1337 Well-Known Member

    Should be (√(x-26) - √x)^2.

    Hypr's already provided a thorough answer, anyway.
     
  14. NekoHennuli

    NekoHennuli Well-Known Member

    Damn, I knew I failed. XD
    But it was fun to do some math problems for a long time. =P
     
  15. nomercy

    nomercy Well-Known Member

    Here are the steps. The trick is to move the sqrt(x) to the right, square both sides, then the x term will cancel on both sides, leaving you with just sqrt(x) and a constant.

    Code:
    sqrt(x-27) + sqrt(x) = 9
    sqrt(x-27) = 9 - sqrt(x)
    sqrt(x-27)^2 = (9 - sqrt(x))^2
    x-27 = 81 - 18*sqrt(x) + sqrt(x)^2
    x-27 = 81 - 18*sqrt(x) + x
    -27 = 81 - 18*sqrt(x)
    -108 = -18*sqrt(x)
    6 = sqrt(x)
    36 = x
    
    Edit: NekoHennuli, line 3: (a+b)^2 is not the same as a^2 + b^2.
     
  16. dink87522

    dink87522 New Member

    I worked it out and got X = 27.
     
  17. tehuber1337

    tehuber1337 Well-Known Member

    Subbing x = 27 into the original equation gives 0 + 5.19... = 9, which is clearly incorrect.

    At any rate, Hypr's already solved this (showing working as required), so this thread doesn't really have a purpose anymore.
     
  18. nomercy

    nomercy Well-Known Member

    It still does. I just supplied the steps to the solution (which apparently nobody figured out or were bothered enough to post...).
     
  19. tehuber1337

    tehuber1337 Well-Known Member

    Admittedly, the steps differ slightly, but oh well.
     
  20. nomercy

    nomercy Well-Known Member

    Awww, people shouldn't post non-bold Solution links... I can hardly notice them...